Calculate the emf of the cell cd/cd2+

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August undefined, 2024

WebFeb 5, 2024 · Standard oxidation potential of Zn is +0.763V and the standard oxidation of potential of Cd is 0.403V. Since, the standard oxidation potential of Zn is more than that of Cd, Zn electrode will act as anode (where oxidation takes place) and Cd will act as cathode (where reduction takes place). WebAug 25, 2024 · CuO flower-like material (FM) was prepared via the facile hydrothermal method, and Ag nanoparticles were deposited on the CuO FM to obtain Ag@CuO composite. Rhodamine 6G (R6G) was used as the probe molecule on Ag@CuO FM substrate to study surface enhanced Raman scattering (SERS). It is discovered that it …

Solved 20#11 Using standard reduction potentials (Appendix E - Chegg

WebCalculate the standard emf of the cell: Cd CdX2+ CuX2+ Cu and determine the cell reaction. The standard reduction potentials of Cu2+ Cu and Cd2+ Cd are 0.34 V and −0.40 volts respectively. WebMar 2, 2024 · To calculate the of the reaction, we use the equation: Putting values in above equation, we get: To calculate the EMF of the cell, we use the Nernst equation, which is: where, = electrode potential of the cell = ? = standard electrode potential of the cell = -0.04 V. n = number of electrons exchanged = 2. Putting values in above equation, we get: john watson obituary florida

Answered: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) E… bartleby

WebAug 17, 2024 · Calculate the potential (emf) of the cell Cd Cd2+(0.10 M) H+ (0.20 M) (Pt, H, (0.5 atm)(Given E' for Cd2+ / … Get the answers you need, now! ... answered … WebCell reaction will be Cd+2H+ → Cd2++H2 (hence n = 2)E°cell = E°right - E°leftE°cell = 0-(-0.403 = + 0.403 V)Ecell = E°cell + 2.303nFlog H+2 CdpH2Cd2+ = 0.403+8.314 × 298 × … WebCHEM1901/3 Answers to Problem Sheet 10 1. (a) Al(s) Al3+(aq) Sn2+(aq) Sn(s) The half reactions and potentials are: Sn2+(aq) + 2e- Sn(s) E° = 0.14 V Al3+(aq) + 3e- Al(s) E° = 1.68 V The Al(s) Al3+(aq) half cell is on the left so this is the oxidation half cell so the half cell reaction is reversed. The Sn2+ Sn(s) half cell is on the right so is the reduction half … how to hack roblox accounts 2022 pc

Solved 1. What is the emf of a galvanic cell consisting of - Chegg

Calculate the standard emf of the cell: Cd Cd^2

WebExample: Predict the cell potential for the following reaction when the pressure of the oxygen gas is 2.50 atm, the hydrogen ion concentration is 0.10 M, and the bromide ion concentration is 0.25 M. O 2 (g) + 4 H + … WebThe equation of the electrochemical cell is then given by Sn Cd Sn Cd2 2+ ++ → + With two half-reactions: Sn e Sn2+ −+ →2 (Cathode, Sn is reduced following the gain of two electrons) Cd Cd e→ +2+ −2 (Anode, Cd is oxidized following the loss of two electrons) Emf of the cell is given by the difference in the reduction potential: 0.136 ... how to hack roblox account backWebQuestion: 20#11 Using standard reduction potentials (Appendix E in the textbook), calculate the standard emf for each of the following reactions. a) Cl2 (g)+2I− (aq)→2Cl− (aq)+I2 (s). E∘ = ______ V b) Ni (s)+2Ce4+ (aq)→Ni2+ (aq)+2Ce3+ (aq). E∘ = ______ V c) Using standard reduction potentials (Appendix E in the textbook), calculate ... how to hack roblox 2022 mobile

"WebChemistry questions and answers. A voltaic cell is constructed that uses the following reaction and operates at 298 K: Zn (s)+Ni2+ (aq)?Zn2+ (aq)+Ni (s). Part A What is the emf of this cell under standard conditions? Express your answer using two significant figures. E? = 0.48 V SubmitMy AnswersGive. " - Calculate the emf of the cell cd/cd2+

Calculate the emf of the cell cd/cd2+

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WebJul 19, 2024 · Calculate the emf of the cell Cd Cd 2+ (0.10M)1 H + (0.20M) Pt, H 2 (0.5 atm) [Given: EºCd 2+ /Cd = – 0.403 V, ... Calculate the potential of the cell at 298 K : Cd/Cd2+ (0.1M) H+ (0.2M)/Pt, H2 … WebJul 6, 2024 · The standard reaction potentials of Ag + /Ag and Cd 2+ /Cd are +0.80 volt and -0.40 volt, respectively. (i) Give the cell representation., (ii) What is the standard cell emf, E°? (iii) What will be the emf of the cell if the concentration of Cd 2+ is 0.1 M and Ag + is 0.2 M.? (iv) Will the cell work spontaneously for the condition given in ...

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WebSolution for For the electrochemical cell Zn (s) Zn2+ (aq) Cd2+ (aq) Cd (s), (a) deduce the cell reaction, (b) calculate the standard emf, ... deduce the cell reaction, (b) … WebWhat is the emf of a galvanic cell consisting of a Cd2+/Cd half-cell and a Pt/H+/H2 half-cell at the following concentrations and pressures? [Cd2+] = 0.97 M [H+] = 0.15 M PH2 = 0.84 atm 2. A constant current is passed through an electrolytic cell containing molten MgCl2 for 16.0 h. If 4.50 × 105 g of Cl2 are obtained, what is the

WebJun 10, 2014 · Cadmium (Cd) is a nonessential microelement and low concentration Cd2+ has strong toxicity to plant growth. Plant metallothioneins, a class of low molecular, cystein(Cys)-rich and heavy-metal binding proteins, play an important role in both metal chaperoning and scavenging of reactive oxygen species (ROS) with their large number … WebIf the local concentration of C u 2 + near the anode and cathode are, respectively, 0.12 M and 0.08 M, the back EMF developed at 298 K is (log 1.5 = 0.18, 2.303 RTF = 0.06) …

WebDec 11, 2024 · Calculate the potential of the cell at 298 K : Cd/Cd 2+ (0.1M) H + (0.2M)/Pt, H 2 (0.5 atm) Given Eº for Cd 2+ /Cd = - 0.403 V, R = 8.314 J-1 mol-1, F = 96500 C mol-1 WebDec 10, 2024 · The electromotive force (EMF) is the maximum potential difference between two electrodes of a galvanic or voltaic cell. This quantity is related to the tendency for an element, a compound or an ion to acquire (i.e. gain) or release (lose) electrons. For example, the maximum potential between Zn and Cu of a well known cell.

WebExpert Answer. Transcribed image text: Calculate the emf of the following concentration cell: Mg(s) Mg2+(0.14M)∥Mg2+(0.75M) Mg(s) Round your answer to 2 significant digits. Note: Reference the Standard reduction potentials at 25∘C table for additional information. how to hack roblox 2022WebSep 9, 2024 · Determine the concentration of Cd2+ ions in the following electrochemical cell: Fe Fe2+ (0.1M) 2. Calculate the emf of a Cd-Cu cell in which Cd is in contact with … john watson secondary schoolWebSep 9, 2024 · Calculate the emf of a Cd-Cu cell in which Cd is in contact with 0.002 M CdSO4 and Cu in contact wit; 2. For the cell, Fe Fe 2+ (0.01 M) Ag+ (0.1 M) Ag, Write the cell reaction and calculate the emf of t; 3. Calculate the potential of Ag-Zn cell at 298 K if the concentration of Ag+ and Zn2+ are 5.2 x 10-6 M; 4. how to hack roblox accounts easilyWebCalculate the standard emf of the cell: Cd CdX2+ CuX2+ Cu and determine the cell reaction. The standard reduction potentials of Cu2+ Cu and Cd2+ Cd are 0.34 V and … how to hack roblox accounts 2022 septemberWebSep 3, 2024 · The standard emf for the given cell reaction Zn + Cu^2+ → Cu + Zn^2+ is 1.10V at 25°C. asked Sep 6, 2024 in Electro Chemistry by Susmita01 ( 46.4k points) … how to hack roblox accountWebMay 23, 2024 · Calculate emf of the following cell Cd/Cd2+ (.10 M)//H+ (.20 M)/H2 (0.5 atm)/Pt [Given E° for Cd2+ /Cd = -0.403 v] LIVE Course for free. Rated by 1 million+ … john watson rooneyWebJun 19, 2024 · Calculate the equilibrium constant for the following equilibruim reaction :- Fe(s) + CD2+ (aq) = Fe 2+ (aq) + Cd (s) ... Calculate the emf of the cell Zn Zn2+ (0.1 M) Cd2+ (0.01 M) Cd at 298 K,[Given E0Zn2+/Zn = - 0.76 V and E0Cd2+/Cd = - 0.40 V ] or (a) Account for the following: (i) Alkaline medium inhibits the rusting of iron. ... how to hack roblox accounts 2021 easy